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Digital pressure gauge _ pressure calibrator > News > Regarding the accuracy problem in the selection of standard digital pressure gauges
Regarding the accuracy problem in the selection of standard digital pressure gauges
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ARIPY

Time : 2020-03-20 17:05 Pageviews : 31

Existing customers have a batch of pressure gauges to be tested, the range is -0.1-1.8MPa, and the accuracy is 0.2. However, I don't know much about the range and accuracy of standard digital pressure gauges. Our PY803 precision digital pressure gauge has a composite range of -0.1-2.5MPa and a full-scale accuracy of 0.05%. Can it meet the verification requirements? Other manufacturers' precision digital pressure gauges have a range of -100kpa---2000kpa and a reading accuracy of 0.1%. Will the effect be better? How do you calculate the accuracy of the standard table? Can you give me a detailed calculation method and basis?

Question answer

The accuracy error of the high-precision digital pressure gauge (including the intelligent pressure calibrator and the precision digital pressure gauge) is calculated according to the full scale (FS%), and the allowable error of (-100~2500) kPa is as follows: ± (upper limit) Value-lower limit) * Accuracy%=±2600*0.05%=±1.3kPa, that is, the allowable error of each calibration point is ±1.3kPa. The accuracy of the digital pressure gauge is for the full-scale error, not applicable to a certain range error. Piston pressure gauges generally calculate the error in the way of reading accuracy, of course, this is also a prerequisite. Some instrument companies use a mixed representation method for accuracy, such as ±(0.1%RD+0.05%FS). This error method increases the reading error on the basis of the full scale. The full range refers to the range of the sensor, and the reading error is for the field range. Therefore, the allowable error is more than twice that of a precision digital pressure gauge with 0.05% FS. For example, ±(0.1%RD+0.05%FS), -100kPa-2000kPa digital meter, at the calibration point of 1000kPa, its tolerance is ±(0.1%*1000+0.05%*2100) kPa=±2.0kPa.



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